## Elementary Geometry for College Students (5th Edition)

First of all, we see that point C is $(5,-3)$, for it is B reflected across the x axis. Now, we can break this into triangles, one below the point (2,1) and one above the point (2,1). By doing this, we can use the distance between (2,1) and (5,3) as the base of each triangle, allowing us to use whole numbers. $A_1 = (1/2)(3)(4) = 6$ $A_2 = (1/2)(3)(2) = 3$ Thus: $A= 3+6 =9$