Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 10 - Section 10.1 - The Rectangular Coordinate System - Exercises: 35

Answer

9

Work Step by Step

First of all, we see that point C is $(5,-3)$, for it is B reflected across the x axis. Now, we can break this into triangles, one below the point (2,1) and one above the point (2,1). By doing this, we can use the distance between (2,1) and (5,3) as the base of each triangle, allowing us to use whole numbers. $A_1 = (1/2)(3)(4) = 6$ $A_2 = (1/2)(3)(2) = 3$ Thus: $A= 3+6 =9$
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