Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 384: 26

Answer

$ A(shaded) = 36 \pi - 54 \sqrt3$

Work Step by Step

Solving for the area of the circle is elementary: $A= \pi r^2 = 36 \pi$ We also know that the area of the hexagon is: $A = 3 \sqrt 3 /2(6^2)$ This gives: $ A(shaded) = 36 \pi - 54 \sqrt3$
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