## Elementary Geometry for College Students (7th Edition)

(32$\pi$ - 64)$in^{2}$
In the circle diameter of the circle = diagonal of the square By pythagoras theorem $diagonal^{2}$ = $8^{2}$ + $8^{2}$ $diagonal^{2}$ = 64 + 64 diagonal = $\sqrt 128$ = 8$\sqrt 2$ in Therefore the diameter of the circle = 8$\sqrt 2$ in Area of the circle = $\pi r^{2}$ = $\pi (4\sqrt 2)^{2}$ = 32$\pi in^{2}$ Area of square = $s^{2}$ = $8^{2}$ = 64 $in^{2}$ Therefore the shaded area = (32$\pi$ - 64)$in^{2}$