Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 384: 21


5 to 13

Work Step by Step

At its minimum, N is the length of AB, so its lower limit is 5. At its maximum, AN is the length of AC. Thus, its upper limit it: $=\sqrt{12^2 + 5^2} =13$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.