Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.4 - Circumference and Area of a Circle - Exercises - Page 384: 21

Answer

5 to 13

Work Step by Step

At its minimum, N is the length of AB, so its lower limit is 5. At its maximum, AN is the length of AC. Thus, its upper limit it: $=\sqrt{12^2 + 5^2} =13$
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