#### Answer

yes

#### Work Step by Step

(9,10,17)
Using Heron's formula if three sides of a triangle have length a,b,c then area A of a triangle is
A = $\sqrt s(s-a)(s-b)(s-c)$
where s = $\frac{a+b+c}{2}$
Lets take a=9 b=10 and c=17
s = $\frac{9+10+17}{2}$
= 18
A = $\sqrt 18(18-9)(18-10)(18-17)$
=$\sqrt 18 *9 * 8 *1$
=36 $unit^{2}$
If a,b,c be the integer length of the sides of the triangle. If area of the triangle is also an integer than (a,b,c) is known as heron triplet.
So area is integer i.e. 36 so (9,10,17) is a heron triples.