Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 371: 35

Answer

624 $ft^{2}$

Work Step by Step

Lets divide the given diagram into two rectangles Dimensions of the rectangle 1 be b= 30ft and h= 18ft As we know the area of the rectangle with the length of the base b and length of the altitude h is A = bh A = 30 * 18 = 540 $ft^{2}$ Now dimensions for the 2 rectangle be b = 14ft and h = 24 -18 = 6ft As we know the area of the rectangle with the length of the base b and length of the altitude h is A = bh A = 14 * 6 = 84$ft^{2}$ Total area of the room = area of 1 rectangle + area of the 2 rectangle = 540 + 84 = 624 $ft^{2}$
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