Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 371: 43

Answer

60$in^{2}$

Work Step by Step

Given a = 5in , b = 1ft = 12 in. c = 1ft = 12 in d = 5in By Brahmaguptas formula, the area of cyclic quadrilateral with sides of length a,b,c and d is A = $\sqrt (s-a)(s-b)(s-c)(s-d)$ s = $\frac{a+b+c +d}{2}$ a = 5 in, b= 12in, c = 12 in, d= 5in s = $\frac{5+12+12+5}{2}$ = 17 in. A = $\sqrt (17-5)(17-12)(17 - 12)(17 - 5)$ =$\sqrt 12 * 5 * 5* 12$ = $\sqrt 5^{2} * 12^{2}$ = 5 *12 = 60$in^{2}$ Therefore the area of the kite = 60 $in^{2}$.
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