Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 106: 25

Answer

$x=45^{\circ}$ $y= 45^{\circ}$

Work Step by Step

$m\angle 3$ = $90^{\circ}+m\angle1$ Putting given values $3x= 90^{\circ} + x$ $x=45^{\circ}$.............................Eq1 Now in $\triangle ABC$ $ m\angle 1+ m\angle 2 = 90^{\circ}$ putting values $x+y= 90^{\circ}$................Eq2 putting value of $x$ from Eq1 in Eq2 $y$= $45^{\circ}$
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