Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 106: 22

Answer

x=90$^{\circ}$ m$\angle$BAC=90$^{\circ}$ m$\angle$B=45$^{\circ}$

Work Step by Step

m$\angle$B+m$\angle$C+m$\angle$BAC=180 $\frac{x}{2}$+$\frac{x}{2}$+x=180 4x=360 x=90$^{\circ}$ m$\angle$BAC=x=90$^{\circ}$ m$\angle$B=$\frac{x}{2}$=45$^{\circ}$
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