Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises - Page 106: 21

Answer

x=72$^{\circ}$ m$\angle$1=72$^{\circ}$ m$\angle$DAE=36$^{\circ}$

Work Step by Step

m$\angle$1+m$\angle$2+m$\angle$DAE=180 x+x+$\frac{x}{2}$=180 5x=360 x=72$^{\circ}$ m$\angle$1=x=72$^{\circ}$ m$\angle$DAE=$\frac{x}{2}$=36$^{\circ}$
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