Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 520: 39

Answer

The distance from the plane to touch down is $\approx 1376.8$ ft.

Work Step by Step

1. Use the sine law to solve for $x$ $\frac{x}{sin90} = \frac{120}{sin5}$ $x = \frac{120sin90}{sin5}$ $x = \frac{120}{0.087155...}$ $x = 1376.845...$ ft $x \approx 1376.8$ ft
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