Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.3 - The Tangent Ratio and Other Ratios - Exercises - Page 520: 36a

Answer

The identity csc α = $\frac{1}{sin α}$ is valid

Work Step by Step

csc α = $\frac{c}{a}$ sin α = $\frac{a}{c}$ $\frac{1}{sin α}$ = $\frac{1}{\frac{a}{c}}$ = $\frac{c}{a}$ So csc α and $\frac{1}{sin α}$ are equivalent
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