Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 505: 36a

Answer

11.5 in

Work Step by Step

The length of segment BC is: $ sin( 90 - \beta) = \frac{CB}{AB}$ $AB sin( 90 - \beta) = CB$ $CB=sin(90-55)(20 in)=11.5 in$
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