Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 505: 32

Answer

$19^{\circ}$

Work Step by Step

Let $\alpha$ be the angle formed by the rope and the water. $\sin\alpha=\frac{4}{12}$ $\alpha=\sin^{-1}\frac{4}{12}$ $\alpha\approx19^{\circ}$
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