Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 505: 29

Answer

$103.5$ ft

Work Step by Step

Let $d$ be the distance between Danny and the balloon. $\sin75^{\circ}=\frac{100}{d}$ $d=\frac{100}{\sin75^{\circ}}$ $d\approx103.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.