Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 11 - Section 11.1 - The Sine Ratio and Applications - Exercises - Page 505: 29


$103.5$ ft

Work Step by Step

Let $d$ be the distance between Danny and the balloon. $\sin75^{\circ}=\frac{100}{d}$ $d=\frac{100}{\sin75^{\circ}}$ $d\approx103.5$
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