#### Answer

(a) $(5,-3,2)$ is a point on the line.
(b) $\langle 1,2,-2 \rangle$ is a direction vector

#### Work Step by Step

$(x,y,z) = (5,-3,2)+n(1,2,-2)$
(a) We can find a point on the line:
When we let $n=0$, $(x,y,z) = (5,-3,2)$
Therefore, $(5,-3,2)$ is a point on the line.
(b) We can let $n=1$ to find a direction vector:
$\langle 1,2,-2 \rangle$ is a direction vector