Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Section 10.6 - The Three-Dimensional Coordinate System - Exercises - Page 490: 16

Answer

The midpoint of the line segment $~\overline{P_1P_2}~$ is: $(1, 4, \frac{9}{2})$

Work Step by Step

$P_1 = (-1,2,3)$ $P_2 = (3,6,6)$ We can find the midpoint between these two points: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} ,\frac{z_1+z_2}{2})$ $= (\frac{-1+3)}{2},\frac{2+6}{2} ,\frac{3+6}{2})$ $ = (1, 4, \frac{9}{2})$ The midpoint of the line segment $~\overline{P_1P_2}~$ is: $(1, 4, \frac{9}{2})$
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