Elementary Geometry for College Students (7th Edition)

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 10 - Section 10.6 - The Three-Dimensional Coordinate System - Exercises - Page 490: 23


$x^2+y^2+z^2 = 25$

Work Step by Step

We can write the general equation of a sphere: $(x-a)^2+(y-b)^2+(z-c)^2 = r^2$ where $(a,b,c)$ is the center of the sphere and $r$ is the radius The center of the sphere is $(0,0,0)$ The radius of the sphere is $5$ We can find an equation for the sphere: $(x-a)^2+(y-b)^2+(z-c)^2 = r^2$ $(x-0)^2+(y-0)^2+(z-0)^2 = (5)^2$ $x^2+y^2+z^2 = 25$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.