Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 9 - Review Exercises - Page 431: 5b

Answer

468 $in.^{2}$

Work Step by Step

Lateral area = perimeter $\times$ h Lateral area = (9 in. + 15 in. + 12 in.) $\times$ 10 in. Lateral area = 360 $in.^{2}$ Base area = $\sqrt (s (s-a)(s-b)(s-c) )$ s= $\frac{9 in. + 15 in. + 12 in.}{2}$ = 18 in. a=9 in. b=15 in. c=12 in. Base area = 54 $in.^{2}$ Total area = 2 $\times$ base area + lateral area Total area = 2 $\times$54 $in.^{2}$ + 360 $in.^{2}$ Total area = 468 $in.^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.