Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 9 - Review Exercises - Page 431: 11c


1296 $in.^{3}$

Work Step by Step

Volume = $\frac{base area \times h}{3}$ Base area = $(18 in.)^{2}$ = 324 $in.^{2}$ h = $\sqrt ( (slant height)^{2} - (\frac{side of the base}{2})^{2})$ h = $\sqrt ( (15 in.)^{2} - (\frac{18 in.}{2})^{2})$ h= 12 in. Volume = $\frac{324 in.^{2} \times 12 in.}{3}$ Volume = 1296 $in.^{3}$
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