## Elementary Geometry for College Students (6th Edition)

We first find the necessary dimensions to find slant height. One leg of a 30-60-90 triangle with half of the base has length: $3 \times (\frac{\sqrt3}{3}) = \sqrt{3}$ Thus, we obtain the value of the slant height: $h = \sqrt{(\sqrt3)^2 + 8^2 } = \sqrt{67}$ Thus, we find: $A = (1/2)(12)(\sqrt{67})(3)=147$