Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 9 - Review Exercises - Page 431: 12a

Answer

147

Work Step by Step

We first find the necessary dimensions to find slant height. One leg of a 30-60-90 triangle with half of the base has length: $3 \times (\frac{\sqrt3}{3}) = \sqrt{3}$ Thus, we obtain the value of the slant height: $ h = \sqrt{(\sqrt3)^2 + 8^2 } = \sqrt{67}$ Thus, we find: $ A = (1/2)(12)(\sqrt{67})(3)=147$
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