## Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole

# Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 360: 23b

#### Answer

$\frac{4}{1}$

#### Work Step by Step

The length of the sides of the first triangle are 6 in, 8 in, 10 in second triangle are 3 in, 4 in, 5 in $\frac{6}{3}$ = $\frac{10}{5}$ =$\frac{8}{4}$ = $\frac{2}{1}$ $\frac{A1}{A2}$ = $(\frac{s1}{s2})^{2}$ = $(\frac{2}{1})^{2}$ = $\frac{4}{1}$

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