## Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole

# Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 360: 23a

#### Answer

$\frac{9}{4}$

#### Work Step by Step

The ratio of the areas of two similar triangles equals the square of the ratio of the lengths of any two corresponding sides; that is, $\frac{A1}{A2}$ = $(\frac{a1}{a2})^{2}$ Given that the ratio of the length of the corresponding sides = $\frac{s1}{s2}$ = $\frac{3}{2}$ The ratio of $\frac{A1}{A2}$ = $(\frac{a1}{a2})^{2}$ = $(\frac{3}{2})^{2}$ = $\frac{9}{4}$

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