## Elementary Geometry for College Students (6th Edition)

240 $m^{2}$
The area of a trapezoid whose bases have lengths b1 and b2 and altitude has length of h is given by A = $\frac{1}{2}$*h(b1+b2) Lets take b1 = BC = 20m b2 =AD = 12m h = 15 m Therefore A = $\frac{1}{2}$*15* (12+20) = 15*(16) = 240 $m^{2}$