Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 351: 53

Answer

48

Work Step by Step

We use trigonometry to obtain: $cos(30^{\circ}) = \frac{s}{8} \\ \\s = 8cos(30^{\circ})$ We square this to obtain: $A = (8cos(30^{\circ}))^2 = 48$
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