Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 351: 51


P = 2x + $\frac{96}{x}$

Work Step by Step

The area of rectangle is 48$in^{2}$ Where x is the width and y is length To express the perimeter P of the rectangle in terms only of x As we know area A of Rectangle A = L*B Given A =48$in^{2}$, l = y and b = x therefore 48 = xy y = $\frac{48}{x}$ As we know the perimeter of rectangle P = 2(l+b) P = 2(y+x) = 2($\frac{48}{x}$ + x) = $\frac{96}{x}$ + 2x P = 2x + $\frac{96}{x}$ .
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