Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 8 - Section 8.1 - Area and Initial Postulates - Exercises - Page 351: 46


$(a+b)^{2}$ = $a^{2}$ + $b^{2}$ + 2ab

Work Step by Step

We know area of square A = side * side The given drawing consist of 4 rectangles The area of Square = (a+b)(a+b)= $(a+b)^{2}$ Lets find the area of all the 4 rectangles separately Rectangle I = ab Rectange II = $b^{2}$ Rectangle III = ab Rectangle IV = $a^{2}$ The total area of square = Area of I + Area of II + Area of III + Area of IV = ab+ $b^{2}$+ab+ $a^{2}$ =2ab+ $b^{2}$ + $a^{2}$ Therefore $(a+b)^{2}$ = $a^{2}$ + $b^{2}$ + 2ab
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.