Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 256: 20


DB=5$\frac{5}{9}$ DC=6$\frac{4}{9}$

Work Step by Step

CD$^2=AB$^2$-$AC$^2$ CD$^2$=400-256 CD=12 $\frac{AB}{BD}$=$\frac{AC}{CD}$ $\frac{20}{BD}$=$\frac{16}{12-BD}$ 240-20BD=16BD 36BD=200 BD=5$\frac{5}{9}$ CD=12-BD CD=6$\frac{4}{9}$
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