Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 256: 17

Answer

NP$\approx$9.8

Work Step by Step

$\frac{NP}{QP}$=$\frac{NM}{MQ}$ $\frac{NP}{8}$=$\frac{12}{NP}$ NP$^2$=96 NP=$\sqrt {96}$$\approx$9.8
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