Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 256: 17

Answer

NP$\approx$9.8

Work Step by Step

$\frac{NP}{QP}$=$\frac{NM}{MQ}$ $\frac{NP}{8}$=$\frac{12}{NP}$ NP$^2$=96 NP=$\sqrt {96}$$\approx$9.8
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.