Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 256: 19



Work Step by Step

NQ bisects $\angle$N because $\frac{NP}{PQ}$=$\frac{NM}{MQ}$ $\angle$N=180-$\angle$M-$\angle$P $\angle$N=180-36-62 $\angle$N=82 2$\angle$QNM=$\angle$N $\angle$QNM=41
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