Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 5 - Section 5.6 - Segments Divided Proportionally - Exercises - Page 256: 19

Answer

$\angle$QNM=41$^{\circ}$

Work Step by Step

NQ bisects $\angle$N because $\frac{NP}{PQ}$=$\frac{NM}{MQ}$ $\angle$N=180-$\angle$M-$\angle$P $\angle$N=180-36-62 $\angle$N=82 2$\angle$QNM=$\angle$N $\angle$QNM=41
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.