Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 248: 31

Answer

BD=4$\sqrt 3$$\approx$6.93

Work Step by Step

2AC=AB AC=6 BC=AC$\sqrt 3$ BC=6$\sqrt 3$ DC$\sqrt 3$=AC DC=2$\sqrt 3$ BD=BC-DC BD=6$\sqrt 3$-2$\sqrt 3$ BD=4$\sqrt 3$$\approx$6.93
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