Answer
DC=2$\sqrt 3$
DB=4$\sqrt 3$
Work Step by Step
2AC=AB
AC=6
CB=AC$\sqrt 3$
CB=6$\sqrt 3$
CD$\sqrt 3$=AC
CD=$\frac{6\sqrt 3}{3}$
CD=2$\sqrt 3$
DB=CB-CD
DB=6$\sqrt 3$-2$\sqrt 3$
DB=4$\sqrt 3$
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 248: 27
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