Answer
BD=4
Work Step by Step
BC=AC$\sqrt 3$
BC=2$\sqrt 3$($\sqrt 3$)
BC=6
DC$\sqrt 3$=AC
DC$\sqrt 3$=2$\sqrt 3$
DC=2
BD=BC-CD
BD=6-2
BD=4
Elementary Geometry for College Students (6th Edition)
by Alexander, Daniel C.; Koeberlein, Geralyn M.
Published by
Brooks Cole
ISBN 10:
9781285195698
ISBN 13:
978-1-28519-569-8
Chapter 5 - Section 5.5 - Special Right Triangles - Exercises - Page 248: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
