Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 240: 8b



Work Step by Step

Let $b=\overline{DE}$ $12^{2}=(6\sqrt 3)^{2}+b^{2}$ $144=108+b^{2}$ Subtract 108 on both sides $36=b^{2}$ $6=b$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.