#### Answer

$(4, 5, 6)$ is not a Pythagorean Triple

#### Work Step by Step

The longest side is always the hypotenuse. $c=6$
Using the Pythagorean Theorem...
$a^{2}+b^{2}=c^{2}$
$4^{2}+5^{2}=6^{2}$
Simplify...
$16+25=36$
$41\ne 36$
Since the equation is not true, the numbers $(4, 5, 6)$ are NOT a Pythagorean Triple.