Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Section 5.4 - The Pythagorean Theorem - Exercises - Page 240: 8a

Answer

$\overline{DE}=12$

Work Step by Step

Let $b = \overline{DE}$ $13^{2} = 5^{2}+ b^{2}$ Isolate $b$ $13^{2}-5^{2}=b^{2}$ $169-25=b^{2}$ $144=b^{2}$ Square root each side $12=b$
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