Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 262: 8e

Answer

$x = 7, -1$

Work Step by Step

$\frac{x-2}{x-5} = \frac{2x+1}{x-1}$ $(x-1)(x-2) = (2x+1)(x-5)$ $x(x-1)-2(x-1) = x(2x+1)-5(2x+1)$ $x^{2}-x -2x +2 = 2x^{2} + x - 10x -5$ $x^{2} -3x + 2 = 2x^{2} -9x - 5$ $2x^{2} -9x - 5= x^{2} -3x + 2$ $x^{2} -6x - 7 = 0$ $(x-7)(x+1) = 0$ $x = 7, -1$
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