Answer
The proof is in the following form:
Column 1 of proof; Column 2 of proof.
Thus, we have:
1. Angle 2 is congruent to angle EDC; vertical angles theorem
2. Angle 1 is congruent to angle 2; given
3. Angle EDC is congruent to angle 1; transitive property
4. Angle A is congruent to itself; identity property
5. Triangles ACD and ABE are similar; AA similarity theorem
6. $\frac{AB}{AC} = \frac{BE}{CD}$; CPSSTP
