Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 5 - Review Exercises - Page 262: 11


$cost = \$210$

Work Step by Step

We can find the cost: $\frac{cost}{12~yd^2} = \frac{\$350}{20~yd^2}$ $cost = (\frac{\$350}{20~yd^2})(12~yd^2)$ $cost = \$210$
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