Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 503: 8


cos α = $\frac{b}{c}$ sin β = $\frac{b}{c}$ Thus cos α = sin β

Work Step by Step

Lets take question 1 diagram: as we know cos α = $\frac{adjacent}{hypotenus}$ for question 1 , cos α = $\frac{12}{13}$ sin β = $\frac{opposite}{hypotenus}$ for question 1 , sin β = $\frac{12}{13}$ Therefore we can say that cos α = sin β = $\frac{12}{13}$
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