Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 503: 3

Answer

cos α = $\frac{3}{5}$, cos β = $\frac{4}{5}$

Work Step by Step

Step 1: By Pythagoras theorem $6^{2}$ + $a^{2}$ = $10^{2}$ $a^{2}$ = 100 - 36 a = $\sqrt 64$ = 8 a = 8 Step 2: cos α = $\frac{length of adjacent}{length of hypotenuse}$ cos α = $\frac{6}{10}$ = $\frac{3}{5}$ Similarly cos β = $\frac{length of adjacent}{length of hypotenuse}$ cos β = $\frac{a}{10}$ =$\frac{8}{10}$ = $\frac{4}{5}$ Therefore cos α = $\frac{3}{5}$, cos β = $\frac{4}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.