Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Chapter 11 - Section 11.2 - The Cosine Ratio and Applications - Exercises - Page 503: 7


sin α = $\frac{a}{c}$ cos β = $\frac{a}{c}$ thus sin α = cos β

Work Step by Step

Lets take question 1 diagram: as we know sin α = $\frac{opposite}{hypotenus}$ for question 1 , sin α = $\frac{5}{13}$ cos β = $\frac{adjacent}{hypotenus}$ for question 1 , cos β = $\frac{5}{13}$ Therefore we can say that sin α = cos β = $\frac{5}{13}$
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