# Chapter 10 - Review Exercises - Page 485: 13

x=4

#### Work Step by Step

A(-2,3) B(x,6) C(8,8) Using Slope formula $m_{AB}$= $\frac{y2-y1}{x2-x1}$ = $\frac{6-3}{x+2}$ $m_{BC}$= $\frac{y2-y1}{x2-x1}$ = $\frac{8-6}{8-x}$ Given that pointrs are collinear, so $m_{AB}$ = $m_{BC}$ $\frac{6-3}{x+2}$ = $\frac{8-6}{8-x}$ 3(8-x) = 2(x+2) 24 - 3x = 2x +4 5x=20 x=4

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