#### Answer

non collinear

#### Work Step by Step

A(-6,5) B(1,7) C(16,10)
Using Slope formula
$m_{AB}$= $\frac{y2-y1}{x2-x1}$ = $\frac{7-5}{1+6}$ = $\frac{2}{7}$
$m_{BC}$= $\frac{y2-y1}{x2-x1}$ = $\frac{10-7}{16-1}$ = $\frac{3}{15}$ =$\frac{1}{5}$
$m_{AB}$ $\ne$ $m_{BC}$
Therefore A,B and C are not collinear.