Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10: 9781285195698
ISBN 13: 978-1-28519-569-8

Appendix A - A.5 - The Quadratic Formula and Square Root Properties - Exercises - Page 555: 38

Answer

$b = 8$

Work Step by Step

We can find the value of $b$: $c^2 = a^2+b^2$ $b^2 = c^2-a^2$ $b^2 = (10)^2+(6)^2$ $b^2 = 100-36$ $b^2 = 64$ $b = \pm \sqrt{64}$ $b = -\sqrt{64}~~$ or $~~b = \sqrt{64}$ $b = -8~~$ or $~~b = 8$ Since the value of $b$ must be positive, $b = 8$
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