Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.5 - The Quadratic Formula and Square Root Properties - Exercises - Page 555: 16

Answer

$a = 5$ $b = 2$ $c=-90$

Work Step by Step

A quadratic equation can be written in this form: $ax^2 + bx+c = 0$ where $a,b,$ and $c$ are real numbers and $a \neq 0$ We can use the quadratic formula to find the solutions of the equation: $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ We can determine the values of $a, b,$ and $c$: $5x^2 = 90-2x$ $5x^2+2x-90 = 0$ $a = 5$ $b = 2$ $c=-90$
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