## Elementary Geometry for College Students (6th Edition)

$c = 5$
We can find the value of $c$: $c^2 = a^2+b^2$ $c^2 = (3)^2+(4)^2$ $c^2 = 9+16$ $c^2 = 25$ $c = \pm \sqrt{25}$ $c = -\sqrt{25}~~$ or $~~c = \sqrt{25}$ $c = -5~~$ or $~~c = 5$ Since the value of $c$ must be positive, $c = 5$