University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter Appendices - Section A.1 - Real Numbers and the Real Line - Exercises - Page AP-6: 8

Answer

Solution set = $\displaystyle \{-\frac{1}{2},-\frac{9}{2}\}$

Work Step by Step

Use properties from the table 'Absolute Values and Intervals". Here, note property 5: $\quad |x|=a \Leftrightarrow x=\pm a,\ \quad $(for any positive number a) Thus, we have: $2t+5=\pm 4\qquad $... add $-5$ $2t=-5\pm 4\qquad $... divide with 2, $t=\displaystyle \frac{-5\pm 4}{2}$ $\displaystyle \frac{-5+4}{2}=-\frac{1}{2}$ $\displaystyle \frac{-5-4}{2}=-\frac{9}{2}$ Solution set = $\displaystyle \{-\frac{1}{2},-\frac{9}{2}\}$
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