Answer
Solution set = $\{-3,3\}$
Work Step by Step
Use properties from the table 'Absolute Values and Intervals".
Here, note property 5:
$\quad |x|=a \Leftrightarrow x=\pm a,\ \quad $(for any positive number a)
Thus, we have:
$y=\pm 3$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter Appendices - Section A.1 - Real Numbers and the Real Line - Exercises - Page AP-6: 7
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