University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter Appendices - Section A.1 - Real Numbers and the Real Line - Exercises - Page AP-6: 10

Answer

$-2\lt x\lt 2,\qquad$ or, $x\in(-2,2)$

Work Step by Step

Use properties from the table 'Absolute Values and Intervals". Apply Property 6: $|x|\lt a\quad\Leftrightarrow\quad -a\lt x\lt a, \quad $ for a = positive number We have: $|x|\lt 2\quad\Leftrightarrow\quad -2\lt x\lt 2$ This is an open interval, $(-2,2)$ See table: "Types of intervals."
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.